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Project Euler Problem 6

The sum of the squares of the first ten natural numbers is, 12 + 22 + ... + 10**2 = 385
The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)2 == 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.\

Project euler problem 6

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Solution to project euler problem 6: Sum square difference

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