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Snake.py
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80 lines (73 loc) · 2.08 KB
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n = int(input())
board = [[0 for _ in range(n)] for _ in range(n)]
k = int(input())
for _ in range(k):
r,c = map(int, input().split())
board[r][c] = 2
l = int(input())
ts = []
for _ in range(l):
time, d = input().split()
time = int(time)
ts.append((time,d))
dx = [0,1,0,-1]
dy = [1,0,-1,0]
head = (0,0) # 행,열
dir = 0
i = 0
# while(head[0] >= 0 and head[0]<n and head[1]>=0 and head[1]<n):
# if (head[0]+dx[dir%4] >= n and head[0]+dy[dir%4] < n):
# break
#
# if (board[head[0]+dx[dir%4]][head[1]+dy[dir%4]]==1):
# break
#
# head = (head[0]+dx[dir%4],head[1]+dy[dir%4])
# print(head)
# if(board[head[0]][head[1]]==2):
# board[head[0]][head[1]] = 1
# else:
# board[tail[0]][tail[1]] = 0
#
# if (i in [t[0] for t in ts]):
# print(i)
# for t in ts:
# if(t[1]=='D'):
# dir += 1
# if(t[1]=='L'):
# dir -= 1
# ts.pop(ts.index(t))
#
# i += 1
# 사과가 있을 경우 꼬리를 머리가 나아간 만큼 떼어내야 하기에, 꼬리를 리스트에 담아두면 좋다.
index = 0 # 시간 감소
x,y=head
board[x][y] = 1
tail = [(x,y)]
while True:
nx = x+dx[dir%4]
ny = y+dy[dir%4] # 나아간 값
print(nx, ny)
if(0<=nx and nx<n and 0<=ny and ny<n and board[nx][ny]!=1):
if(board[nx][ny]==0):
# 없을 경우 이전 꼬리(1칸당 기록했던 것 중 최근 것)은 잘라내야함
# 사과 없음
board[nx][ny] = 1
tail.append((nx, ny)) # 저장
px, py = tail.pop(0)
board[px][py] = 0
if(board[nx][ny]==2):
board[nx][ny] = 1
tail.append((nx, ny))
else:
i += 1
break
x,y = nx, ny # 머리의 이동(방향만큼 1칸 이동) - 새로운 머리
i += 1
if index<l and i==ts[index][0]:
if(ts[index][1]=='L'):
dir -= 1
if(ts[index][1]=='D'):
dir += 1
index += 1
print(i)