StringsAndThings.java

package io.zipcoder;


import java.util.regex.Matcher;
import java.util.regex.Pattern;

/**
 * @author tariq
 */
public class StringsAndThings {

    /**
     * Given a string, count the number of words ending in 'y' or 'z' -- so the 'y' in "heavy" and the 'z' in "fez" count,
     * but not the 'y' in "yellow" (not case sensitive). We'll say that a y or z is at the end of a word if there is not an alphabetic
     * letter immediately following it. (Note: Character.isLetter(char) tests if a char is an alphabetic letter.)
     * example : countYZ("fez day"); // Should return 2
     *           countYZ("day fez"); // Should return 2
     *           countYZ("day fyyyz"); // Should return 2
     */
    public Integer countYZ(String input){
        int result = 0;
        for (int i = 0; i < input.length(); i++) {
            if (input.charAt(i) == 'y' || input.charAt(i) == 'z') {
                result += 1;
            }
        }
        return result;
    } // This one needs refinement - only pass two cases - need more work in the if statement
      // This method counts all (given) letters inside of a string

    /**
     * Given two strings, base and remove, return a version of the base string where all instances of the remove string have
     * been removed (not case sensitive). You may assume that the remove string is length 1 or more.
     * Remove only non-overlapping instances, so with "xxx" removing "xx" leaves "x".
     *
     * example : removeString("Hello there", "llo") // Should return "He there"
     *           removeString("Hello there", "e") //  Should return "Hllo thr"
     *           removeString("Hello there", "x") // Should return "Hello there"
     */
    public String removeString(String base, String remove){
        String result = base.replace(remove, "");

        return result;
    }

    /**
     * Given a string, return true if the number of appearances of "is" anywhere in the string is equal
     * to the number of appearances of "not" anywhere in the string (case sensitive)
     *
     * example : containsEqualNumberOfIsAndNot("This is not")  // Should return false
     *           containsEqualNumberOfIsAndNot("This is notnot") // Should return true
     *           containsEqualNumberOfIsAndNot("noisxxnotyynotxisi") // Should return true
     */
    public Boolean containsEqualNumberOfIsAndNot(String input){

        Integer resultIs = 0;
        Integer resultNot = 0;
        for (int i = 0; i < input.length() - 1; i++) {
            char is = 'i';
            char is2 = 's';
            char not = 'n';
            char not1 = 'o';
            char not2 = 't';
            if (input.charAt(i) == is && input.charAt(i + 1) == is2) {
                resultIs++;
            }
            if (input.charAt(i) == not && input.charAt(i + 1) == not1 && input.charAt(i + 2) == not2) {
                resultNot++;
            }
        }
        if (resultIs.equals(resultNot)) {
            return true;
        }
        return false;
    }
    // This current state of code (input.matches(String) returns test 2 & 3
    // Previous state of code (input.contains(String) returns test 1
    // Interesting...
    // But!! If I use input.charAt(i) and type out variables for each letter...I pass 1 and 2 but not 3

    /**
     * We'll say that a lowercase 'g' in a string is "happy" if there is another 'g' immediately to its left or right.
     * Return true if all the g's in the given string are happy.
     * example : gHappy("xxggxx") // Should return  true
     *           gHappy("xxgxx") // Should return  false
     *           gHappy("xxggyygxx") // Should return  false
     */
    public Boolean gIsHappy(String input){
        String checkValue = "gg";
        if(!input.contains(checkValue)) {
         return false;
        }
        return true;
    }


    /**
     * We'll say that a "triple" in a string is a char appearing three times in a row.
     * Return the number of triples in the given string. The triples may overlap.
     * example :  countTriple("abcXXXabc") // Should return 1
     *            countTriple("xxxabyyyycd") // Should return 3
     *            countTriple("a") // Should return 0
     */
    public Integer countTriple(String input){
        input.toLowerCase();
        int result = 0;
        for (int i = 0; i < input.length() -2; i++)
        {
            char possibleSeq = input.charAt(i);
            if (possibleSeq == input.charAt(i+1) && possibleSeq == input.charAt(i+2))
                result++;
        }
        return result;
    }
}